1985 AMC 8 Problem 7

Attempt Problem 7 of the 1985 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1985 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

A "stair-step" figure is made up of alternating black and white squares in each row. Rows 11 through 44 are shown. All rows begin and end with a white square. The number of black squares in the 3737th row is

3434

3535

3636

3737

3838

Answer: C
Concepts:pattern recognitionbasic counting

Difficulty rating: 860

Solution:

Row nn contains 2n12n - 1 squares. Because both ends are white and the colors alternate, each row has one more white square than black square, so the number of black squares is n1.n - 1.

For the 3737th row, this is 371=36.37 - 1 = 36.

Thus, the correct answer is C .

← Problem 6#6Full ExamProblem 8#8 →

Problem 7 in Other Years

1986 AMC 8 · 1987 AMC 8 · 1988 AMC 8 · 1989 AMC 8 · 1990 AMC 8 · 1991 AMC 8 · 1992 AMC 8 · 1993 AMC 8 · 1994 AMC 8 · 1995 AMC 8 · 1996 AMC 8 · 1997 AMC 8 · 1998 AMC 8 · 1999 AMC 8 · 2000 AMC 8 · 2001 AMC 8 · 2002 AMC 8 · 2003 AMC 8 · 2004 AMC 8 · 2005 AMC 8 · 2006 AMC 8 · 2007 AMC 8 · 2008 AMC 8 · 2009 AMC 8 · 2010 AMC 8 · 2011 AMC 8 · 2012 AMC 8 · 2013 AMC 8 · 2014 AMC 8 · 2015 AMC 8 · 2016 AMC 8 · 2017 AMC 8 · 2018 AMC 8 · 2019 AMC 8 · 2020 AMC 8 · 2022 AMC 8 · 2023 AMC 8 · 2024 AMC 8 · 2025 AMC 8 · 2026 AMC 8