1989 AMC 8 Problem 7 — Solution | LIVE by Po-Shen Loh

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1989 AMC 8 Problem 7

Below is the professionally curated solution for Problem 7 of the 1989 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1989 AMC 8 solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:money linear equation

Difficulty rating: 770

7.

The value of $20$ quarters and $10$ dimes equals the value of $10$ quarters and $n$ dimes. What is $n?$

$10$

$20$

$30$

$35$

$45$

Solution:

The value of $20$ quarters and $10$ dimes is $\$5.00 + \$1.00 = \$6.00.$

Ten quarters are worth $\$2.50,$ so the $n$ dimes must supply $\$6.00 - \$2.50 = \$3.50.$ That is $35$ dimes, so $n = 35.$

Thus, the correct answer is D .

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