1989 AMC 8 Problem 7 — Solution | LIVE by Po-Shen Loh

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1989 AMC 8 Problem 7

Attempt Problem 7 of the 1989 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1989 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

The value of $20$ quarters and $10$ dimes equals the value of $10$ quarters and $n$ dimes. What is $n?$

$10$

$20$

$30$

$35$

$45$

Answer: D

Concepts:money linear equation

Difficulty rating: 770

Solution:

The value of $20$ quarters and $10$ dimes is $\$5.00 + \$1.00 = \$6.00.$

Ten quarters are worth $\$2.50,$ so the $n$ dimes must supply $\$6.00 - \$2.50 = \$3.50.$ That is $35$ dimes, so $n = 35.$

Thus, the correct answer is D .

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