1991 AMC 8 Problem 7

Attempt Problem 7 of the 1991 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1991 AMC 8 solutions, or check the answer key.

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7.

The value of (487,000)(12,027,300)+(9,621,001)(487,000)(19,367)(.05)\tiny\frac{(487{,}000)(12{,}027{,}300) + (9{,}621{,}001)(487{,}000)}{(19{,}367)(.05)} is closest to

10,000,00010{,}000{,}000

100,000,000100{,}000{,}000

1,000,000,0001{,}000{,}000{,}000

10,000,000,00010{,}000{,}000{,}000

100,000,000,000100{,}000{,}000{,}000

Answer: D
Concepts:estimationdistributive property

Difficulty rating: 890

Solution:

Factor the numerator: 487,000487{,}000 (12,027,300+9,621,001).\cdot\, (12{,}027{,}300 + 9{,}621{,}001).

Rounding to leading digits, this is about 500,000500{,}000 ×(10,000,000+10,000,000)\times (10{,}000{,}000 + 10{,}000{,}000) =500,000×2= 500{,}000 \times 2 ×107.\times 10^{7}. The denominator is about 20,000×.05=1000.20{,}000 \times .05 = 1000.

So the value is roughly 500,000×2×1071000\dfrac{500{,}000 \times 2 \times 10^{7}}{1000} =1010= 10^{10} =10,000,000,000.= 10{,}000{,}000{,}000.

Thus, the correct answer is D .

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