2025 AMC 8 Problem 6

Below is the video solution and professionally curated solution for Problem 6 of the 2025 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 8 solutions, or check the answer key.

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Concepts:modular arithmeticdivisibility

Difficulty rating: 900

6.

Sekou writes the numbers 15,15, 16,16, 17,17, 18,18, 19.19. After he erases one of the numbers, the sum of the remaining four numbers is a multiple of 4.4. Which number did he erase?

1515

1616

1717

1818

1919

Video solution:
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Written solution:

The remainders of the five numbers after dividing by 44 are: 3,3, 0,0, 1,1, 2,2, and 3.3. So, the sum of all five numbers modulo 44 is the same as 3+0+1+2+3=93 + 0 + 1 + 2 + 3 = 9 which has remainder 11 modulo 4.4. Therefore, in order to erase a single number and get a sum that is 00 modulo 4,4, we must erase the number which was 11 modulo 4,4, which was 17.17. Therefore, the answer is C.

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