1993 AMC 8 Problem 2 — Solution | LIVE by Po-Shen Loh

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1993 AMC 8 Problem 2

Below is the professionally curated solution for Problem 2 of the 1993 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:fraction greatest common divisor

Difficulty rating: 450

2.

When the fraction $\dfrac{49}{84}$ is expressed in simplest form, then the sum of the numerator and the denominator will be

$11$

$17$

$19$

$33$

$133$

Solution:

Since $49 = 7 \times 7$ and $84 = 7 \times 12,$ the fraction reduces to $\dfrac{7}{12}.$

The sum of numerator and denominator is $7 + 12 = 19.$

Thus, the correct answer is C .

← Problem 1#1 Full Exam Problem 3#3 →

Problem 2 in Other Years

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