1989 AMC 8 Problem 2 — Solution | LIVE by Po-Shen Loh

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1989 AMC 8 Problem 2

Attempt Problem 2 of the 1989 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1989 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

What is the value of

$\frac{2}{10} + \frac{4}{100} + \frac{6}{1000}?$

$.012$

$.0246$

$.12$

$.246$

$246$

Answer: D

Concepts:decimal place value

Difficulty rating: 450

Solution:

Each fraction is a decimal in a different place: $\frac{2}{10} = .2,$ $\frac{4}{100} = .04,$ and $\frac{6}{1000} = .006.$

Adding these gives $.2 + .04 + .006 = .246.$

Thus, the correct answer is D .

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