1991 AMC 8 Problem 2 — Solution | LIVE by Po-Shen Loh

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1991 AMC 8 Problem 2

Attempt Problem 2 of the 1991 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1991 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

What is the value of $\frac{16+8}{4-2}?$

$4$

$8$

$12$

$16$

$20$

Answer: C

Concepts:order of operations whole number operations

Difficulty rating: 450

Solution:

$\frac{16+8}{4-2} = \frac{24}{2} = 12.$

Thus, the correct answer is C .

← Problem 1#1 Full Exam Problem 3#3 →

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