2016 AMC 8 Problem 2

Attempt Problem 2 of the 2016 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

In rectangle ABCD,ABCD, AB=6AB=6 and AD=8.AD=8. Point MM is the midpoint of AD.\overline{AD}. What is the area of AMC?\triangle AMC?

12 12

15 15

18 18

20 20

24 24

Answer: A
Concepts:triangle areamidpoint
Difficulty rating: 450
Small Hint:

Since MM is the midpoint of AD\overline{AD}, find AMAM.

Big Hint:

Use AMAM as the base and the rectangle’s vertical side length as the height.

Video solution:
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Written solution:

Since MM is the midpoint of AD,\overline{AD}, the base AMAM has length 4.4. The altitude from CC to AM\overline{AM} has length AB=6.AB=6. The area is therefore 1246=12.\dfrac{1}{2} \cdot 4 \cdot 6 = 12.

Thus, A is the correct answer.

Problem 1#1
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