1993 AMC 8 Problem 1 — Solution | LIVE by Po-Shen Loh

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1993 AMC 8 Problem 1

Below is the professionally curated solution for Problem 1 of the 1993 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:fraction

Difficulty rating: 560

1.

Which pair of numbers does not have a product equal to $36?$

$\{-4, -9\}$

$\{-3, -12\}$

$\left\{\dfrac12, -72\right\}$

$\{1, 36\}$

$\left\{\dfrac32, 24\right\}$

Solution:

Checking each pair: $(-4)(-9) = 36,$ $(-3)(-12) = 36,$ $\dfrac12 \times (-72) = -36,$ $(1)(36) = 36,$ and $\dfrac32 \times 24 = 36.$

Only $\dfrac12 \times (-72) = -36$ fails to equal $36.$

Thus, the correct answer is C .

Full Exam Problem 2#2 →

Problem 1 in Other Years

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