1990 AMC 8 Problem 1
Below is the professionally curated solution for Problem 1 of the 1990 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1990 AMC 8 solutions, or check the answer key.
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Difficulty rating: 930
1.
What is the smallest sum of two -digit numbers that can be obtained by placing each of the six digits into one of the six boxes of a sum of two -digit numbers?
Solution:
To make the sum small, the two smallest digits go in the hundreds places, the next two in the tens places, and the two largest in the units places.
One such arrangement is , and every arrangement of this type gives the same sum.
Thus, the correct answer is C .
Problem 1 in Other Years
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