1994 AMC 8 Problem 1 — Solution | LIVE by Po-Shen Loh

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1994 AMC 8 Problem 1

Below is the professionally curated solution for Problem 1 of the 1994 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:fraction

Difficulty rating: 560

1.

Which of the following is the largest?

$\dfrac{1}{3}$

$\dfrac{1}{4}$

$\dfrac{3}{8}$

$\dfrac{5}{12}$

$\dfrac{7}{24}$

Solution:

Over the common denominator $24$ , the fractions are $\dfrac{8}{24}, \dfrac{6}{24}, \dfrac{9}{24}, \dfrac{10}{24},$ and $\dfrac{7}{24}.$

The largest numerator is $10$ , so $\dfrac{5}{12} = \dfrac{10}{24}$ is the largest.

Thus, the correct answer is D .

Full Exam Problem 2#2 →

Problem 1 in Other Years

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