1993 AMC 8 Problem 2 — Solution | LIVE by Po-Shen Loh

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1993 AMC 8 Problem 2

Below is the professionally curated solution for Problem 2 of the 1993 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:fraction greatest common divisor

Difficulty rating: 450

2.

When the fraction $\dfrac{49}{84}$ is expressed in simplest form, then the sum of the numerator and the denominator will be

$11$

$17$

$19$

$33$

$133$

Solution:

Since $49 = 7 \times 7$ and $84 = 7 \times 12,$ the fraction reduces to $\dfrac{7}{12}.$

The sum of numerator and denominator is $7 + 12 = 19.$

Thus, the correct answer is C .

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Problem 2 in Other Years

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