2025 AMC 12A Problem 1

Attempt Problem 1 of the 2025 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Andy and Betsy both live in Mathville. Andy leaves Mathville on his bicycle at 1:30,1{:}30, traveling due north at a steady 88 miles per hour. Betsy leaves on her bicycle from the same point at 2:30,2{:}30, traveling due east at a steady 1212 miles per hour. At what time will they be exactly the same distance from their common starting point?
3:303{:}30
3:453{:}45
4:004{:}00
4:154{:}15
4:304{:}30
Answer: E
Concepts:distance rate and timelinear equation
Small hint:
Measure time from 1:301{:}30; Betsy has been riding one hour less than Andy
Big hint:
If Andy has ridden tt hours, set 8t=12(t−1)8t = 12(t-1)
Solution:
Let tt be the number of hours since 1:30.1{:}30. Andy has traveled 8t8t miles north, and Betsy, who started an hour later, has traveled 12(t−1)12(t-1) miles east.
Setting the distances equal, 8t=12(t−1),8t = 12(t-1), so 4t=124t = 12 and t=3.t = 3.
Three hours after 1:301{:}30 is 4:30.4{:}30.
Thus, the correct answer is E.
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