2022 AMC 12B Problem 11

Attempt Problem 11 of the 2022 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12B solutions, or check the answer key.

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11.

Let f(n)=(1+i32)n+(1i32)n, \begin{aligned} f(n) &= \left(\dfrac{-1 + i\sqrt3}{2}\right)^n \\ &\quad {}+ \left(\dfrac{-1 - i\sqrt3}{2}\right)^n, \end{aligned} where i=1.i = \sqrt{-1}. What is f(2022)?f(2022)?

2-2

1-1

00

3\sqrt3

22

Answer: E
Concepts:roots of unitycomplex number
Difficulty rating: 1570
Solution:

The two bases are the primitive cube roots of unity, ω=e2πi/3\omega = e^{2\pi i/3} and its conjugate ω2=e2πi/3.\omega^2 = e^{-2\pi i/3}. So f(n)=ωn+ωn=2cos2πn3.f(n) = \omega^n + \omega^{-n} = 2\cos\dfrac{2\pi n}{3}.

Since 20222022 is a multiple of 3,3, ω2022=1,\omega^{2022} = 1, so f(2022)=1+1=2.f(2022) = 1 + 1 = 2.

Thus, the correct answer is E.

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