2022 AMC 12B Problem 11

Attempt Problem 11 of the 2022 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12B solutions, or check the answer key.

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11.

Let f(n)=(−1+i32)n+(−1−i32)n, \begin{aligned} f(n) &= \left(\dfrac{-1 + i\sqrt3}{2}\right)^n \\ &\quad {}+ \left(\dfrac{-1 - i\sqrt3}{2}\right)^n, \end{aligned} where i=−1.i = \sqrt{-1}. What is f(2022)?f(2022)?
−2-2
−1-1
00
3\sqrt3
22
Answer: E
Concepts:roots of unitycomplex number
Small hint:
The two bases are the primitive cube roots of unity, ω\omega and ω2\omega^2
Big hint:
Then f(n)=ωn+ω−n;f(n) = \omega^n + \omega^{-n}; reduce the exponent 20222022 modulo 33
Solution:
The two bases are the primitive cube roots of unity, ω=e2πi3\omega = e^{\frac{2\pi i}{3}} and its conjugate ω2=e−2πi3.\omega^2 = e^{-\frac{2\pi i}{3}}. So f(n)=ωn+ω−n=2cos⁡2πn3.f(n) = \omega^n + \omega^{-n} = 2\cos\dfrac{2\pi n}{3}.
Since 20222022 is a multiple of 3,3, ω2022=1,\omega^{2022} = 1, so f(2022)=1+1=2.f(2022) = 1 + 1 = 2.
Thus, the correct answer is E.
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