2017 AMC 12B Problem 11

Below is the professionally curated solution for Problem 11 of the 2017 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12B solutions, or check the answer key.

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Concepts:subsetsbijectioninclusion-exclusion

Difficulty rating: 1590

11.

Call a positive integer monotonous if it is a one-digit number or its digits, when read from left to right, form either a strictly increasing or a strictly decreasing sequence. For example, 3,3, 23578,23578, and 987620987620 are monotonous, but 88,88, 7434,7434, and 2355723557 are not. How many monotonous positive integers are there?

10241024

15241524

15331533

15361536

20482048

Solution:

Strictly increasing monotonous numbers correspond to nonempty subsets of {1,,9},\{1, \ldots, 9\}, giving 291=511.2^9 - 1 = 511. Strictly decreasing ones correspond to subsets of {0,1,,9}\{0, 1, \ldots, 9\} other than \varnothing and {0}\{0\} (a leading 00 is not allowed), giving 2102=1022.2^{10} - 2 = 1022. The nine single-digit numbers are counted in both, so the total is 511+10229=1524.511 + 1022 - 9 = 1524.

Thus, the correct answer is B.

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