2022 AMC 12B Problem 10

Below is the professionally curated solution for Problem 10 of the 2022 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12B solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:regular polygondistance formulacoordinate geometry

Difficulty rating: 1500

10.

Regular hexagon ABCDEFABCDEF has side length 2.2. Let GG be the midpoint of AB,\overline{AB}, and let HH be the midpoint of DE.\overline{DE}. What is the perimeter of GCHF?GCHF?

434\sqrt3

88

454\sqrt5

474\sqrt7

1212

Solution:

Place the hexagon with center at the origin: A=(1,3),A = (-1, \sqrt3), B=(1,3),B = (1, \sqrt3), C=(2,0),C = (2, 0), D=(1,3),D = (1, -\sqrt3), E=(1,3),E = (-1, -\sqrt3), F=(2,0).F = (-2, 0).

Then G=(0,3)G = (0, \sqrt3) and H=(0,3).H = (0, -\sqrt3). By symmetry all four sides of GCHFGCHF are equal, and GC=22+(3)2=7. GC = \sqrt{2^2 + (\sqrt3)^2} = \sqrt7.

The perimeter is 47.4\sqrt7.

Thus, the correct answer is D.

Problem 10 in Other Years