2019 AMC 12B Problem 10

Below is the professionally curated solution for Problem 10 of the 2019 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 12B solutions, or check the answer key.

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Concepts:graph theoryparitycasework

Difficulty rating: 1640

10.

The figure below is a map showing 1212 cities and 1717 roads connecting certain pairs of cities. Paula wishes to travel along exactly 1313 of those roads, starting at city AA and ending at city L,L, without traveling along any portion of a road more than once. (Paula is allowed to visit a city more than once.) How many different routes can Paula take?

00

11

22

33

44

Solution:

A route uses 1313 roads as an open trail from AA to L,L, so on the used roads exactly AA and LL have odd degree and every other city has even degree.

In the full map the corner cities AA and LL already have even degree 2,2, and six edge-cities have odd degree 3.3. Removing 44 roads must flip the parity of A,A, L,L, and those six cities, and of no others. This forces the four removed roads to pair up those eight cities in the only possible way, so the set of 1313 used roads is uniquely determined.

Counting the Eulerian trails from AA to LL on that graph gives exactly 44 routes.

Thus, E is the correct answer.

Problem 10 in Other Years