2020 AMC 12B Problem 1

Attempt Problem 1 of the 2020 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

What is the value in simplest form of the following expression?
1+1+3+1+3+5+1+3+5+7 \begin{aligned} &\sqrt{1} + \sqrt{1+3} + \sqrt{1+3+5} \\ &\quad {}+ \sqrt{1+3+5+7} \end{aligned}
55
4+7+104 + \sqrt{7} + \sqrt{10}
1010
1515
4+33+25+74 + 3\sqrt{3} + 2\sqrt{5} + \sqrt{7}
Answer: C
Concepts:sum of first n odd numbersperfect squareradical
Small hint:
The sum of the first kk odd numbers is k2k^2
Big hint:
Each term simplifies to 1,\sqrt{1}, 4,\sqrt{4}, 9,\sqrt{9}, and 16\sqrt{16}
Solution:
The sum of the first kk odd numbers equals k2,k^2, so each radicand is a perfect square: 1+4+9+16=1+2+3+4=10. \begin{aligned} &\sqrt{1} + \sqrt{4} + \sqrt{9} + \sqrt{16} \\ &= 1 + 2 + 3 + 4 = 10. \end{aligned}
Thus, the correct answer is C.
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