2016 AMC 12A Problem 11

Attempt Problem 11 of the 2016 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

Each of the 100100 students in a certain summer camp can either sing, dance, or act. Some students have more than one talent, but no student has all three talents. There are 4242 students who cannot sing, 6565 students who cannot dance, and 2929 students who cannot act. How many students have two of these talents?
1616
2525
3636
4949
6464
Answer: E
Concepts:complementary countinginclusion-exclusiondouble counting
Small hint:
Count how many students can do each activity
Big hint:
Adding the three counts tallies two-talent students twice; subtract 100100
Solution:
The numbers who can sing, dance, and act are 100−42=58,100-42=58, 100−65=35,100-65=35, and 100−29=71,100-29=71, respectively, for a total of 58+35+71=164.58+35+71=164.
Since no student has all three talents, each student has one or two talents, so single-talent students are counted once and two-talent students are counted twice. The number counted twice is 164−100=64.164-100=64.
Thus, the correct answer is E.
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