2013 AMC 12A Problem 1 — Solution | LIVE by Po-Shen Loh

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2013 AMC 12A Problem 1

Attempt Problem 1 of the 2013 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Square $ABCD$ has side length $10.$ Point $E$ is on $\overline{BC},$ and the area of $\triangle ABE$ is $40.$ What is $BE?$

$4$

$5$

$6$

$7$

$8$

Answer: E

Concepts:triangle area right triangle

Difficulty rating: 840

Solution:

The legs of right triangle $ABE$ are $AB = 10$ and $BE.$ From $\tfrac12\cdot 10\cdot BE = 40,$ we get $BE = 8.$

Thus, the correct answer is E.

Problem 2#2 →

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