2008 AMC 12B Problem 1

Attempt Problem 1 of the 2008 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

A basketball player made 55 baskets during a game. Each basket was worth either 22 or 33 points. How many different numbers could represent the total points scored by the player?
22
33
44
55
66
Answer: E
Concepts:counting integers in a range
Small hint:
The total is smallest with all 22-point baskets and largest with all 33-point baskets
Big hint:
Every integer between 5⋅25 \cdot 2 and 5⋅35 \cdot 3 is attainable
Solution:
The total ranges from 5⋅2=105 \cdot 2 = 10 (all two-pointers) to 5⋅3=155 \cdot 3 = 15 (all three-pointers). Swapping one two-pointer for a three-pointer raises the total by exactly 1,1, so every integer in between occurs.
The possible totals are 10,11,12,13,14,15,10, 11, 12, 13, 14, 15, which is 66 values.
Thus, the correct answer is E.
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