2007 AMC 12B Problem 1

Attempt Problem 1 of the 2007 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Isabella’s house has 33 bedrooms. Each bedroom is 1212 feet long, 1010 feet wide, and 88 feet high. Isabella must paint the walls of all the bedrooms. Doorways and windows, which will not be painted, occupy 6060 square feet in each bedroom. How many square feet of walls must be painted?
678678
768768
786786
867867
876876
Answer: E
Concepts:perimeterarea
Small hint:
The four walls of a room form a band of height 88 wrapping around the floor
Big hint:
The painted area per room is (floor perimeter)×\times(height)−60-60
Solution:
The perimeter of each bedroom floor is 2(12+10)=442(12+10)=44 feet.
So the wall area in one bedroom is 44⋅8−60=352−60=29244\cdot8-60=352-60=292 square feet. Across all three bedrooms, Isabella paints 3⋅292=8763\cdot292=876 square feet.
Thus, the correct answer is E.
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