1996 AMC 12 Problem 11

Attempt Problem 11 of the 1996 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1996 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

Given a circle of radius 2,2, there are many line segments of length 22 that are tangent to the circle at their midpoints. Find the area of the region consisting of all such line segments.
π4\frac{\pi}{4}
4−π4-\pi
π2\frac{\pi}{2}
π\pi
2π2\pi
Answer: D
Concepts:geometric lociannulus area
Small hint:
Each tangent segment extends one unit in each direction from its midpoint
Big hint:
Use a right triangle from the circle’s center to locate the inner and outer radii of the swept region
Solution:
Each segment is centered at a tangency point 22 units from the circle’s center and extends 11 unit along the tangent in both directions. As the tangency point rotates, the segments fill the annulus with inner radius 22 and outer radius 22+12=5.\sqrt{2^2+1^2}=\sqrt5. Its area is π(5−4)=π,\pi(5-4)=\pi, so the correct answer is D.
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