1992 AMC 12 Problem 1

Attempt Problem 1 of the 1992 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

If 3(4x+5π)=P,3(4x+5\pi)=P, then 6(8x+10π)=6(8x+10\pi)=
2P2P
4P4P
6P6P
8P8P
18P18P
Answer: B
Concepts:algebraic scalingdistributive property
Small hint:
Compare 8x+10π8x+10\pi with 4x+5π4x+5\pi
Big hint:
Account separately for the change inside the parentheses and the change in the outside coefficient
Solution:
We have 8x+10π=2(4x+5π),8x+10\pi=2(4x+5\pi), so 6(8x+10π)=12(4x+5π)=4[3(4x+5π)]=4P. \begin{gathered} 6(8x+10\pi)\\ {}=12(4x+5\pi)\\ {}=4\bigl[3(4x+5\pi)\bigr]\\ {}=4P. \end{gathered}
Thus the correct answer is B.
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