1988 AMC 12 Problem 13

Attempt Problem 13 of the 1988 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 12 solutions, or check the answer key.

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13.

If sin⁡x=3cos⁡x,\sin x=3\cos x, then what is sin⁡xcos⁡x?\sin x\cos x?
16\frac16
15\frac15
29\frac29
14\frac14
310\frac3{10}
Answer: E
Concepts:trigonometric identitiesalgebraic substitution
Small hint:
Square the given relation and use sin⁡2x+cos⁡2x=1\sin^2x+\cos^2x=1
Big hint:
The given relation also determines the sign of the product
Solution:
Squaring gives sin⁡2x=9cos⁡2x.\sin^2x=9\cos^2x. Hence 10cos⁡2x=1.10\cos^2x=1. Multiplying sin⁡x=3cos⁡x\sin x=3\cos x by cos⁡x\cos x gives sin⁡xcos⁡x=3cos⁡2x=310.\sin x\cos x=3\cos^2x=\frac{3}{10}.
Thus the correct answer is E.
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