1960 AMC 12 Problem 37

Attempt Problem 37 of the 1960 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1960 AMC 12 solutions, or check the answer key.

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37.

The base of a triangle is of length b,b, and the altitude is of length h.h. A rectangle of height xx is inscribed in the triangle with the base of the rectangle in the base of the triangle. The area of the rectangle is:

bxh(hx)\dfrac{bx}{h}(h-x)

hxb(bx)\dfrac{hx}{b}(b-x)

bxh(h2x)\dfrac{bx}{h}(h-2x)

x(bx)x(b-x)

x(hx)x(h-x)

Answer: A
Concepts:similarityrectanglearea
Difficulty rating: 1280
Small Hint:

At height x,x, use similarity to find the horizontal width of the triangle

Big Hint:

The available width is b(1xh)b(1-\frac{x}{h}); multiply it by the rectangle’s height

Solution:

The cross-section parallel to the base at height xx has width b(1xh)=b(hx)h b\left(1-\frac{x}{h}\right)=\frac{b(h-x)}{h} by similarity. Multiplying by the rectangle’s height xx gives bxh(hx). \frac{bx}{h}(h-x).

Thus, the correct answer is A.

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Problem 37 in Other Years

1950 AMC 12 · 1951 AMC 12 · 1952 AMC 12 · 1953 AMC 12 · 1954 AMC 12 · 1955 AMC 12 · 1956 AMC 12 · 1957 AMC 12 · 1958 AMC 12 · 1959 AMC 12 · 1961 AMC 12 · 1962 AMC 12 · 1963 AMC 12 · 1964 AMC 12 · 1965 AMC 12 · 1966 AMC 12 · 1967 AMC 12