1960 AMC 12 Problem 36

Attempt Problem 36 of the 1960 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1960 AMC 12 solutions, or check the answer key.

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36.

Let s1,s_1, s2,s_2, s3s_3 be the respective sums of n,n, 2n,2n, 3n3n terms of the same arithmetic progression with aa as the first term and dd as the common difference. Let R=s3s2s1.R=s_3-s_2-s_1. Then RR is dependent on:

aa and dd

dd and nn

aa and nn

a,a, d,d, and nn

neither aa nor dd nor nn

Answer: B
Concepts:arithmetic sequencesummationalgebraic manipulation
Difficulty rating: 1670
Small Hint:

Use Sk=k2(2a+(k1)d)S_k=\dfrac{k}{2}(2a+(k-1)d)

Big Hint:

Substitute k=n,2n,3nk=n,2n,3n and collect the aa-terms and dd-terms separately

Solution:

Using the arithmetic-series formula, sj=jn2(2a+(jn1)d). s_j=\frac{jn}{2}\bigl(2a+(jn-1)d\bigr). In s3s2s1,s_3-s_2-s_1, the coefficient of aa is 3n2nn=0.3n-2n-n=0. Simplifying the remaining terms gives R=2n2d. R=2n^2d. Thus RR depends on dd and n,n, but not on a.a.

Therefore, the correct answer is B.

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Problem 36 in Other Years

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