1953 AMC 12 Problem 36

Attempt Problem 36 of the 1953 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1953 AMC 12 solutions, or check the answer key.

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36.

Determine mm so that 4x26x+m4x^2-6x+m is divisible by x3.x-3. The obtained value, m,m, is an exact divisor of:

1212

2020

3636

4848

6464

Answer: C
Concepts:factor theoremdivisibilitypolynomial
Difficulty rating: 1280
Small Hint:

Use the factor theorem at x=3x=3

Big Hint:

After finding m,m, test which listed number is divisible by it

Solution:

Divisibility by x3x-3 requires 4(3)26(3)+m=0, 4(3)^2-6(3)+m=0, so 18+m=018+m=0 and m=18.m=-18. Of the listed numbers, only 3636 is an exact multiple of 18.-18.

Thus, the correct answer is C.

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Problem 36 in Other Years

1950 AMC 12 · 1951 AMC 12 · 1952 AMC 12 · 1954 AMC 12 · 1955 AMC 12 · 1956 AMC 12 · 1957 AMC 12 · 1958 AMC 12 · 1959 AMC 12 · 1960 AMC 12 · 1961 AMC 12 · 1962 AMC 12 · 1963 AMC 12 · 1964 AMC 12 · 1965 AMC 12 · 1966 AMC 12 · 1967 AMC 12