2023 AMC 10A Problem 6

Attempt Problem 6 of the 2023 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

An integer is assigned to each vertex of a cube. The value of an edge is defined to be the sum of the values of the two vertices it touches, and the value of a face is defined to be the sum of the values of the four edges surrounding it. The value of the cube is defined as the sum of the values of its six faces. Suppose the sum of the integers assigned to the vertices is 21.21. What is the value of the cube?
4242
6363
8484
126126
252252
Answer: D
Concepts:double countingcube geometry
Small hint:
Each edge belongs to 22 faces, so the total face value is 22 times the total edge value
Big hint:
Each vertex belongs to 33 edges, so the total edge value is 33 times the vertex total
Solution:
Count by incidences. Each edge lies on 22 faces, so the six face values together are 22 times the total of all edge values. Each vertex lies on 33 edges, so the total edge value is 33 times the vertex sum. Chaining these, the cube’s value is 2⋅3⋅21=126.2 \cdot 3 \cdot 21 = 126. Therefore, the answer is D.
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