2022 AMC 10A Problem 6

Below is the professionally curated solution for Problem 6 of the 2022 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 10A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:absolute valueradical

Difficulty rating: 900

6.

Which expression is equal to a2(a1)2\left|a-2-\sqrt{(a-1)^2}\right| for a<0?a < 0?

32a3 - 2a

1a1 - a

11

a+1a + 1

33

Solution:

By the definition of square root, we get that (a1)2=a1.\sqrt{(a - 1)^2} = |a - 1|.

Since a<0,a < 0, we get that a1<0,a - 1 < 0, which means that a1=1a.|a - 1| = 1 - a.

The whole expression therefore simplifies to a2(1a)=2a3. |a - 2 - (1 - a)| = |2a - 3|. Since a<0,a < 0, we know that 2a3<0.2a - 3 < 0. This means that 2a3=32a.|2a - 3| = 3 - 2a.

Thus, A is the correct answer.

Problem 6 in Other Years