2023 AMC 10B Problem 6

Attempt Problem 6 of the 2023 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10B solutions, or check the answer key.

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6.

Let L1=1,L_1 = 1, L2=3,L_2 = 3, and Ln+2=Ln+1+LnL_{n+2} = L_{n+1} + L_n for n1.n \ge 1. How many terms in the sequence L1,L_1, L2,L_2, L3,L_3, ,\ldots, L2023L_{2023} are even?

673673

10111011

675675

10101010

674674

Answer: E
Concepts:parityrecursionpattern recognition
Difficulty rating: 1250
Small Hint:

Track only the parity of the terms: odd, odd, even, and then it repeats

Big Hint:

Even terms occur exactly at positions that are multiples of 33

Solution:

Track the parities: 1,3,4,7,11,18,1, 3, 4, 7, 11, 18, \ldots run odd, odd, even, then repeat with period 3.3. So LnL_n is even exactly when nn is divisible by 3.3. Among 1n2023,1 \le n \le 2023, that’s 20233=674\lfloor \frac{2023}{3} \rfloor = 674 multiples of 3.3. Therefore, the answer is E.

Problem 5#5
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