2013 AMC 10B Problem 6

Below is the professionally curated solution for Problem 6 of the 2013 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10B solutions, or check the answer key.

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Concepts:mean

Difficulty rating: 900

6.

The average age of 3333 fifth-graders is 11.11. The average age of 5555 of their parents is 33.33. What is the average age of all of these parents and fifth-graders?

22 22

23.25 23.25

24.75 24.75

26.25 26.25

28 28

Solution:

The sum of the ages of all the fifth-graders and their parents is: 3311+5533=6633.33\cdot 11+55\cdot 33 = 66\cdot 33.

Then, as the average is the sum divided by the number of people, the average age must be: 663388=3433=24.75.\dfrac{66\cdot 33}{88} = \dfrac 34 \cdot 33 = 24.75 .

Thus, the correct answer is C .

Problem 6 in Other Years