2021 AMC 10B Fall Problem 24

Attempt Problem 24 of the 2021 AMC 10B Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10B Fall solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

24.

A cube is constructed from 44 white unit cubes and 44 blue unit cubes. How many different ways are there to construct the 2×2×22 \times 2 \times 2 cube using these smaller cubes? (Two constructions are considered the same if one can be rotated to match the other.)
7 7
8 8
9 9
10 10
11 11
Answer: A
Concepts:Burnside’s Lemmacube geometry
Small hint:
This is the number of 44-vertex subsets of a cube up to rotation
Big hint:
Burnside over the 2424 rotations of the cube
Solution:
This is the number of ways to choose which 44 of the 88 cube vertices are blue, up to cube rotation. Use Burnside’s lemma on the 2424 rotations of the cube.
The identity fixes (84)=70\binom84=70 colorings. The 66 quarter-turn face rotations each fix 2.2. The 33 half-turn face rotations each fix 6.6. The 88 rotations about opposite vertices each fix 4.4. The 66 half-turn rotations about opposite edges each fix 6.6.
Thus the number of inequivalent constructions is 70+6⋅2+3⋅6+8⋅4+6⋅624=7. \begin{gathered} \frac{70+6\cdot2+3\cdot6+8\cdot4+6\cdot6}{24}\\ =7. \end{gathered}
Thus, the answer is A .
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