2023 AMC 10B Problem 24

Below is the professionally curated solution for Problem 24 of the 2023 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10B solutions, or check the answer key.

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Concepts:coordinate geometryvectorperimeter

Difficulty rating: 2470

24.

What is the perimeter of the boundary of the region consisting of all points which can be expressed as (2u3w, v+4w)(2u - 3w,\ v + 4w) with 0u1,0 \le u \le 1, 0v1,0 \le v \le 1, and 0w1?0 \le w \le 1?

10310\sqrt{3}

1010

1212

1818

1616

Solution:

Fix w.w. As u,vu, v sweep [0,1]2,[0, 1]^2, the point (2u3w, v+4w)(2u - 3w,\ v + 4w) fills a 2×12 \times 1 axis-aligned rectangle with lower-left corner (3w,4w).(-3w, 4w). Now let ww run from 00 to 1.1. The rectangle slides along the vector (3,4),(-3, 4), which has length 5.5. So the region is the Minkowski sum of that rectangle and the segment, and its perimeter is the rectangle's perimeter plus twice the segment length: 2(2+1)+25=16.2(2 + 1) + 2 \cdot 5 = 16. Therefore, the answer is E.

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