2009 AMC 10B Problem 24

Below is the professionally curated solution for Problem 24 of the 2009 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10B solutions, or check the answer key.

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Concepts:regular polygonangle sumsymmetry

Difficulty rating: 1600

24.

The keystone arch is an ancient architectural feature. It is composed of congruent isosceles trapezoids fitted together along the non-parallel sides, as shown. The bottom sides of the two end trapezoids are horizontal. In an arch made with 99 trapezoids, let xx be the angle measure in degrees of the larger interior angle of the trapezoid. What is x?x?

100100

102102

104104

106106

108108

Solution:

Adding a mirror image completes the arch into a symmetric closed loop of 1818 trapezoids. Their inner edges form a regular 1818-gon, each interior angle of which is (182)18018=160. \dfrac{(18-2)\cdot180^\circ}{18}=160^\circ.

At each inner vertex, two of the trapezoids' larger angles xx meet the 160160^\circ angle around a full turn: x+x+160=360,x+x+160^\circ=360^\circ, so x=100.x=100.

Thus, the correct answer is A.

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