2021 AMC 10A Fall Problem 6

Attempt Problem 6 of the 2021 AMC 10A Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Fall solutions, or check the answer key.

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6.

Elmer the emu takes 4444 equal strides to walk between consecutive telephone poles on a rural road. Oscar the ostrich can cover the same distance in 1212 equal leaps. The telephone poles are evenly spaced, and the 4141st pole along this road is exactly one mile (52805280 feet) from the first pole. How much longer, in feet, is Oscar's leap than Elmer's stride?

66

88

1010

1111

1515

Answer: B
Concepts:ratio and proportionunit conversionfencepost counting
Difficulty rating: 870
Solution:

There are 4040 gaps between the 11st and 4141st pole, which means that the distance between consecutive poles is 5280÷40=132 5280 \div 40 = 132 feet.

This means that each of Elmer's strides is 132÷44=3 132 \div 44 = 3 feet. Similarly, each of Oscar's leaps is 132÷12=11 132 \div 12 = 11 feet. This makes Oscar's leap 113=811 - 3 = 8 feet longer.

Thus, B is the correct answer.

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