2020 AMC 10B Problem 20

Attempt Problem 20 of the 2020 AMC 10B below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

Let BB be a right rectangular prism (box) with edge lengths 1,1, 3,3, and 4,4, together with its interior. For real r≥0,r\geq0, let S(r)S(r) be the set of points in 33-dimensional space that lie within a distance rr of some point in B.B. The volume of S(r)S(r) can be expressed as ar3+br2+cr+d,ar^{3} + br^{2} + cr +d, where a,a, b,b, c,c, and dd are positive real numbers. What is bcad?\dfrac{bc}{ad}?
66
1919
2424
2626
3838
Answer: B
Concepts:volume3D geometryrectangular prism
Small hint:
Decompose the enlarged solid into the original box, face slabs, edge quarter-cylinders, and corner eighth-spheres
Big hint:
The coefficient of r2r^2 comes from one quarter-cylinder along each edge
Video solution:
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Written solution:
Decompose S(r)S(r) by where the added volume lies relative to the box.
The original box has volume d=1⋅3⋅4=12.d=1\cdot3\cdot4=12. The face slabs contribute surface area times r,r, so c=2(1⋅3+1⋅4+3⋅4)=38.c=2(1\cdot3+1\cdot4+3\cdot4)=38.
Along each edge is a quarter-cylinder of radius r.r. The sum of all edge lengths is 4(1+3+4)=32,4(1+3+4)=32, so b=14π⋅32=8π.b=\frac14\pi\cdot 32=8\pi. At the eight corners, the eighth-spheres combine to one full sphere, so a=43π.a=\frac43\pi.
Therefore bcad=(8π)(38)(43π)(12)=19.\frac{bc}{ad}=\frac{(8\pi)(38)}{(\frac43\pi)(12)}=19.
Thus, the correct answer is B .
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