2020 AMC 10B Problem 20

Attempt Problem 20 of the 2020 AMC 10B below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 10B solutions, or check the answer key.

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20.

Let BB be a right rectangular prism (box) with edge lengths 1,1, 3,3, and 4,4, together with its interior. For real r0,r\geq0, let S(r)S(r) be the set of points in 33-dimensional space that lie within a distance rr of some point in B.B. The volume of S(r)S(r) can be expressed as ar3+br2+cr+d,ar^{3} + br^{2} + cr +d, where a,a, b,b, c,c, and dd are positive real numbers. What is bcad?\dfrac{bc}{ad}?

66

1919

2424

2626

3838

Answer: B
Concepts:volume3D geometryrectangular prism
Difficulty rating: 2150
Video solution:
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Written solution:

Decompose S(r)S(r) by where the added volume lies relative to the box.

The original box has volume d=134=12.d=1\cdot3\cdot4=12. The face slabs contribute surface area times r,r, so c=2(13+14+34)=38.c=2(1\cdot3+1\cdot4+3\cdot4)=38.

Along each edge is a quarter-cylinder of radius r.r. The sum of all edge lengths is 4(1+3+4)=32,4(1+3+4)=32, so b=14π32=8π.b=\frac14\pi\cdot 32=8\pi. At the eight corners, the eighth-spheres combine to one full sphere, so a=43π.a=\frac43\pi.

Therefore bcad=(8π)(38)(43π)(12)=19.\frac{bc}{ad}=\frac{(8\pi)(38)}{(\frac43\pi)(12)}=19.

Thus, the correct answer is B .

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