2016 AMC 10A Problem 20

Attempt Problem 20 of the 2016 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

For some particular value of N,N, when (a+b+c+d+1)N(a+b+c+d+1)^N is expanded and like terms are combined, the resulting expression contains exactly 10011001 terms that include all four variables a,a, b,b, c,c, and d,d, each to some positive power. What is N?N?
99
1414
1616
1717
1919
Answer: B
Concepts:stars and barscombinations
Small hint:
Count exponent choices for terms containing all four variables
Big hint:
Stars and bars gives (N4)=1001\binom N4=1001
Solution:
A term that includes all four variables has form avbwcxdya^vb^wc^xd^y, with v,w,x,y≥1v,w,x,y\ge1, multiplied by some power of 11. If that power is zz, then v+w+x+y+z=N.v+w+x+y+z=N.
After subtracting 11 from each of v,w,x,yv,w,x,y, this becomes a nonnegative stars-and-bars count with 55 variables summing to N−4N-4. The number of such terms is (N4).\binom{N}{4}.
Since (144)=1001\binom{14}{4}=1001, we get N=14N=14.
Thus, the correct answer is B.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.