2016 AMC 10A Problem 14

Attempt Problem 14 of the 2016 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

How many ways are there to write 20162016 as the sum of twos and threes, ignoring order? (For example, 1008⋅2+0⋅31008\cdot 2 + 0\cdot 3 and 402⋅2+404⋅3402\cdot 2 + 404\cdot 3 are two such ways.)
236236
336336
337337
403403
672672
Answer: C
Concepts:Diophantine Equationparity
Small hint:
Write 2x+3y=20162x+3y=2016
Big hint:
yy must be even from 00 through 672672
Solution:
The problem can be rewritten as an equation 2x+3y=2016,2x + 3y = 2016, where xx is the number of twos and yy is the number of threes.
The goal is to find the number of multiples of 33 that can be subtracted from 20162016 to result in an even number.
This can be achieved by the pairs of (1008,0)(1008, 0) up to (0,672)(0, 672) with yy being incremented by 2.2.
This gives us 6722+1=337\dfrac{672}{2} + 1 = 337 solutions for yy and x.x.
Thus, the correct answer is C .
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