2016 AMC 10A Problem 13

Below is the professionally curated solution for Problem 13 of the 2016 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:logical deductioninvariant

Difficulty rating: 1420

13.

Five friends sat in a movie theater in a row containing 55 seats, numbered 11 to 55 from left to right. (The directions "left" and "right" are from the point of view of the people as they sit in the seats.)

During the movie Ada went to the lobby to get some popcorn. When she returned, she found that Bea had moved two seats to the right, Ceci had moved one seat to the left, and Dee and Edie had switched seats, leaving an end seat for Ada. In which seat had Ada been sitting before she got up?

11

22

33

44

55

Solution:

Note that Dee and Edie do not change the answers since their seats remain occupied throughout.

Since Bea moves to the right, this forces Ada and Ceci to move to offset this disruption.

Ceci only moves one seat, so Ada must also move one to cancel out the two seat shift that Bea did.

Bea moved to the right and Ceci moved to the left, so Ada must also move to the left to get a total displacement of 0.0.

Therefore, Ada must have started off in seat 22 to move one to the left to end up in seat 1.1.

Thus, the correct answer is B .

Problem 13 in Other Years