2006 AMC 10B Problem 13

Below is the professionally curated solution for Problem 13 of the 2006 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 10B solutions, or check the answer key.

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Concepts:mixtureratio and proportion

Difficulty rating: 1340

13.

Joe and JoAnn each bought 1212 ounces of coffee in a 1616-ounce cup. Joe drank 22 ounces of his coffee and then added 22 ounces of cream. JoAnn added 22 ounces of cream, stirred the coffee well, and then drank 22 ounces. What is the resulting ratio of the amount of cream in Joe's coffee to that in JoAnn's coffee?

67\dfrac{6}{7}

1314\dfrac{13}{14}

11

1413\dfrac{14}{13}

76\dfrac{7}{6}

Solution:

Joe adds 22 ounces of cream and drinks nothing afterward, so he has 22 ounces of cream.

JoAnn has 1212 ounces of coffee plus 22 ounces of cream, making 1414 ounces of uniform mixture. After drinking 22 ounces she keeps 1214=67\tfrac{12}{14}=\tfrac67 of her cream, which is 672=127\tfrac67\cdot2=\tfrac{12}{7} ounces.

The ratio is 2÷127=76.2\div\tfrac{12}{7}=\tfrac{7}{6}.

Thus, the correct answer is E.

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