2014 AMC 10B Problem 1

Attempt Problem 1 of the 2014 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Leah has 1313 coins, all of which are pennies and nickels. If she had one more nickel than she has now, then she would have the same number of pennies and nickels. In cents, how much are Leah’s coins worth?
33 33
35 35
37 37
39 39
41 41
Answer: C
Concepts:linear equationmoney
Small hint:
Translate the nickel condition into an equation for pennies and nickels
Big hint:
Use the total of 1313 coins after finding the two counts
Solution:
Let the number of pennies be p.p. Then, the number of nickels is 13−p13-p and p−1,p-1, so 13−p=p−1.13-p=p-1. This means we have 77 pennies and 66 nickels.
Therefore, the number of cents is 7+6⋅5=37.7+6\cdot 5=37.
Thus, the correct answer is C .
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