2014 AMC 10B Problem 11

Attempt Problem 11 of the 2014 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 10B solutions, or check the answer key.

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11.

For the consumer, a single discount of n%n\% is more advantageous than any of the following discounts:
(1)(1) Two successive 15%15\% discounts.
(2)(2) Three successive 10%10\% discounts.
(3)(3) A 25%25\% discount followed by a 5%5\% discount.
What is the smallest possible positive integer value of n?n?
  27 \ \ 27
 28 \ 28
 29 \ 29
 31 \ 31
 33 \ 33
Answer: C
Concepts:percentageinequality
Small hint:
Convert each stacked discount into the final fraction of the price paid
Big hint:
The single discount must exceed the largest of the three effective discounts
Solution:
The three successive-discount plans leave the customer paying 0.852=0.7225,0.93=0.729,0.75(0.95)=0.7125 \begin{aligned} 0.85^2&=0.7225,\\ 0.9^3&=0.729,\\ 0.75(0.95)&=0.7125 \end{aligned} times the listed price. Their effective discounts are therefore 27.75%27.75\%, 27.1%27.1\%, and 28.75%28.75\%.
A single n%n\% discount must exceed all three, so n>28.75n>28.75. The smallest positive integer that works is 2929.
Thus, the correct answer is C .
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