2013 AMC 10B Problem 11

Attempt Problem 11 of the 2013 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10B solutions, or check the answer key.

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11.

Real numbers xx and yy satisfy the equation x2+y2=10x−6y−34.x^2+y^2=10x-6y-34. What is x+y?x+y?
1 1
2 2
3 3
6 6
8 8
Answer: B
Concepts:completing the square
Small hint:
Move all terms to one side and complete two squares
Big hint:
A sum of squares equals zero only when both squares are zero
Solution:
This can be rewritten as x2−10x+y2+6y+34=0.x^2-10x+y^2+6y+34=0.
Completing the square yields x2−10x+25+y2+6y+9x^2-10x+25+y^2+6y+9 =(x−5)2+(y+3)2=(x-5)^2+(y+3)^2 =0.=0. Since both squared terms are nonnegative and their sum is 0,0, both must be 00. Thus (x−5)2=(y+3)2=0.(x-5)^2 = (y+3)^2=0.
Therefore, x=5,y=−3,x=5,y=-3, so x+y=2.x+y=2.
Thus, the correct answer is B.
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