2012 AMC 10B Problem 1

Attempt Problem 1 of the 2012 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Each third-grade classroom at Pearl Creek Elementary has 1818 students and 22 pet rabbits. How many more students than rabbits are there in all 44 of the third-grade classrooms?
48 48
56 56
64 64
72 72
80 80
Answer: C
Concepts:whole number operations
Small hint:
Find the student-rabbit difference in one classroom first
Big hint:
Multiply that difference by 44 classrooms
Solution:
Each classroom has 18−2=1618-2=16 more students than rabbits.
Across 44 classrooms, the difference is 4⋅16=644\cdot16=64.
Thus, C is the correct answer.
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