2012 AMC 10A Problem 11

Attempt Problem 11 of the 2012 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

Externally tangent circles with centers at points AA and BB have radii of lengths 55 and 3,3, respectively. A line externally tangent to both circles intersects ray ABAB at point C.C. What is BC?BC?
44
4.84.8
10.210.2
1212
14.414.4
Answer: D
Concepts:tangent circlestangent linesimilarity
Small hint:
Draw radii to the two tangent points
Big hint:
The two right triangles with vertex CC are similar
Solution:
Let xx be BC.BC. Note that △CEB\triangle CEB and △CDA\triangle CDA are similar due to angle-angle (tangent lines are perpendicular to radii).
Then x3=8+x5. \dfrac{x}{3} = \dfrac{8 + x}{5}. Cross-multiplying gives us 5x=24+3x 5x = 24 + 3x x=12. x = 12.
Thus, D is the correct answer.
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