2009 AMC 10A Problem 20

Attempt Problem 20 of the 2009 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

Andrea and Lauren are 2020 kilometers apart. They bike toward one another with Andrea traveling three times as fast as Lauren, and the distance between them decreasing at a rate of 11 kilometer per minute. After 55 minutes, Andrea stops biking because of a flat tire and waits for Lauren. After how many minutes from the time they started to bike does Lauren reach Andrea?
2020
3030
5555
6565
8080
Answer: D
Concepts:distance rate and timerate
Small hint:
Let Lauren’s rate be r;r; then r+3r=1r + 3r = 1 kilometer per minute
Big hint:
Find the distance left after 55 minutes, then the time for Lauren to cover it alone
Solution:
Let Lauren’s rate be rr km/min. Then r+3r=1,r + 3r = 1, so r=14.r = \dfrac14.
In the first 55 minutes the gap shrinks by 55 km, leaving 1515 km. Lauren covers this alone at 14\dfrac14 km/min, taking 1514=60\dfrac{15}{\frac{1}{4}} = 60 minutes.
The total time is 5+60=655 + 60 = 65 minutes.
Thus, the correct answer is D.
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