2009 AMC 10A Problem 21

Below is the professionally curated solution for Problem 21 of the 2009 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.

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Concepts:tangent circlesarea ratiorationalizing denominator

Difficulty rating: 1690

21.

Many Gothic cathedrals have windows with portions containing a ring of congruent circles that are circumscribed by a larger circle. In the figure shown, the number of smaller circles is four. What is the ratio of the sum of the areas of the four smaller circles to the area of the larger circle?

3223 - 2\sqrt{2}

222 - \sqrt{2}

4(322)4(3 - 2\sqrt{2})

12(32)\dfrac{1}{2}(3 - \sqrt{2})

2222\sqrt{2} - 2

Solution:

Let each small circle have radius 1.1. Their centers form a square of side 2,2, whose diagonal is 22.2\sqrt2.

The large circle's diameter is 2+22,2 + 2\sqrt2, so its radius is 1+2.1 + \sqrt2.

The desired ratio is 4π(1)2π(1+2)2=43+22=4(322).\dfrac{4 \cdot \pi (1)^2}{\pi (1 + \sqrt2)^2} = \dfrac{4}{3 + 2\sqrt2} = 4(3 - 2\sqrt2).

Thus, the correct answer is C.

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