2007 AMC 10B Problem 1

Attempt Problem 1 of the 2007 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Isabella’s house has 33 bedrooms. Each bedroom is 1212 feet long, 1010 feet wide, and 88 feet high. Isabella must paint the walls of all the bedrooms. Doorways and windows, which will not be painted, occupy 6060 square feet in each bedroom. How many square feet of walls must be painted?
678678
768768
786786
867867
876876
Answer: E
Concepts:surface areaperimeter
Small hint:
Each bedroom has four walls; find the total wall area from the perimeter and the height
Big hint:
Multiply the room’s perimeter by its height, then subtract 6060
Solution:
The walls of one bedroom have area 2(12+10)⋅8=44⋅8=3522(12+10)\cdot 8 = 44\cdot 8 = 352 square feet. Subtracting the 6060 square feet of doorways and windows leaves 352−60=292352-60=292 square feet per bedroom.
With 33 bedrooms, the total is 3⋅292=8763\cdot 292 = 876 square feet.
Thus, the correct answer is E.
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