2005 AMC 10B Problem 6

Attempt Problem 6 of the 2005 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

At the beginning of the school year, Lisa’s goal was to earn an A on at least 80%80\% of her 5050 quizzes for the year. She earned an A on 2222 of the first 3030 quizzes. If she is to achieve her goal, on at most how many of the remaining quizzes can she earn a grade lower than an A?
11
22
33
44
55
Answer: B
Concepts:percentageinequality
Small hint:
Find how many A’s she needs in total
Big hint:
She needs 0.8⋅500.8\cdot50 A’s, and 2020 quizzes remain
Solution:
Lisa needs an A on at least 0.8⋅50=400.8 \cdot 50 = 40 quizzes.
She already has 22,22, so she needs 40−22=1840 - 22 = 18 A’s among the remaining 2020 quizzes.
That leaves at most 20−18=220 - 18 = 2 quizzes with a grade lower than an A.
Thus, B is the correct answer.
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